產生1~x個不重覆的數字，用java內建api

import java.util.List;

import java.util.*;

public class test{

public static void main(String args[])

{

int N1,N2,N3,N4,N5,N6,bonus;

ArrayList numbers = new ArrayList();

for(int i=1;i<=7;i++)

{

numbers.add(i);

}

// numbers.add(1~42);

Collections.shuffle(numbers);

N1=Integer.parseInt(numbers.get(0).toString());
N2=Integer.parseInt(numbers.get(1).toString());
N3=Integer.parseInt(numbers.get(2).toString());
N4=Integer.parseInt(numbers.get(3).toString());
N5=Integer.parseInt(numbers.get(4).toString());
N6=Integer.parseInt(numbers.get(5).toString());
bonus=Integer.parseInt(numbers.get(6).toString());

System.out.println(N1);
System.out.println(N2);
System.out.println(N3);
System.out.println(N4);
System.out.println(N5);
System.out.println(N6);
System.out.println(bonus);

}

}